Solved B Determine The Velocity Component At Theta 40 Degreesc B. determine the velocity component at theta = 40 degrees. c.determine the maximum acceleration along with a certain value theta. show transcribed image text. there are 2 steps to solve this one. created by chegg. The equation for the distance traveled by a projectile being affected by gravity is sin(2θ)v 2 g, where θ is the angle, v is the initial velocity and g is acceleration due to gravity. assuming that v 2 g is constant, the greatest distance will be when sin(2θ) is at its maximum, which is when 2θ = 90 degrees. this means θ = 45 degrees.
Solved In The Problem To The Right Theta 40 Degrees And The Motor Projectile motion solved examples: a projectile is fired from a cliff with a height of $200\, {\rm m}$ at an angle of $37^\circ$ from the horizontal with an initial velocity of $150\, {\rm m s}$. find the following: (a) the distance at which the projectile hit the ground. (b) the maximum height above the ground reached by the projectile. Projectile equations used in the calculator and solver. the vector initial velocity has two components: v0x and v0y given by: v0x = v0 cos (θ) v0y = v0 sin (θ) the vector acceleration a has two components a x and a y given by: (acceleration along the y axis only) ax = 0 and ay = g = 9.8 m s2. at time t, the velocity has two components. The two parts of a vector are known as components and describe the influence of that vector in a single direction. if a projectile is launched at an angle to the horizontal, then the initial velocity of the projectile has both a horizontal and a vertical component. the horizontal velocity component (vx) describes the influence of the velocity. Video answer: we're told that our velocity field is x, squared minus y squared plus x in the x direction and minus 2 x y plus y in the y direction and we're taking the point p, which is x y equals 12 point. first of all, we want to calculate the.
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